这个不定积分咋算?

2个回答

  • ∫{[2^(x-1)+3^(x-1)]/5^x}dx

    =∫[2^(x-1)/5^x]dx+∫[3^(x-1)/5^x]dx

    =(1/2)∫(2/5)^xdx+(1/3)∫(3/5)^xdx

    =(1/2)(2/5)^x/ln(2/5)+(1/3)(3/5)^x/ln(3/5)+C.