因式分解(x^5+x^4+5x^2+5x+6)/(x^2+x+1)

1个回答

  • ( x^5 + x^4 + 5x" + 5x + 6 ) / ( x" + x + 1 )

    先想想,怎样约分,去分母

    = ( x^5 + x^4 + x"' - x"' - x" - x + 6x" + 6x + 6 ) / ( x" + x + 1 )

    = [ x"'( x" + x + 1 ) - x( x" + x + 1 ) + 6( x" + x + 1 ) ] / ( x" + x + 1 )

    = ( x" + x + 1 )( x"' - x + 6 ) / ( x" + x + 1 )

    = x"' - x + 6

    下面还是用立方和、立方差分解

    = x"' + 8 - x - 2

    = ( x"' + 2"' ) - ( x + 2 )

    = ( x + 2 )( x" - 2x + 4 ) - ( x + 2 )

    = ( x + 2 )( x" - 2x + 3 )