原式=∫6√xdx-∫x√xdx
=6∫x^1/2dx-∫x^3/2dx
=6*x^(1/2+1)/(1/2+1)-x^(3/2+1)/(3/2+1)+C
=4x√x-2/5*x²√x+C
∫(6-X)×√Xdx根号下X乘于（6-x）的不定积分是多少,
原式=∫6√xdx-∫x√xdx
=6∫x^1/2dx-∫x^3/2dx
=6*x^(1/2+1)/(1/2+1)-x^(3/2+1)/(3/2+1)+C
=4x√x-2/5*x²√x+C