1.
(x²+px+3)(x²-2x+q)
=x⁴+(p-2)x³+(q+3-2p)x²+3q
因乘积中不含x²和x³项.
∴p-2=0且q+3-p=0
∴p=2,q=-1
2
∵q=-1∴q+1=0
(q+1)²+(q-3)(q+3)+(q-3)(q+1)
=(q-3)(q+3)
=(-1-3)(-1+3)
=-4×2
=-8
1.
(x²+px+3)(x²-2x+q)
=x⁴+(p-2)x³+(q+3-2p)x²+3q
因乘积中不含x²和x³项.
∴p-2=0且q+3-p=0
∴p=2,q=-1
2
∵q=-1∴q+1=0
(q+1)²+(q-3)(q+3)+(q-3)(q+1)
=(q-3)(q+3)
=(-1-3)(-1+3)
=-4×2
=-8