Question

在△ABC中,∠B与∠C的角平行线交于点P,过点B作BF//PC交AC的延长线于点F,过点C作CE//BP的延长线于点E

Answer 1

∵BP//EC

∴∠ABP = ∠E

∠PBC = ∠BCE

∵BP是∠ABC的平分线

∴∠ABP = ∠PBC

∴∠E = ∠BCE

∴EB = CB

同理∠F = ∠CBF

∴BE=CF

∴EB = CF