通项an=n+(1/2)^n
前6项之和=1+2+3+4+5+6+(1/2)^1+(1/2)^2+(1/2)^3+(1/2)^4+(1/2)^5+(1/2)^6
(1+6)x6/2 +1/2【1-(1/2)^6】/(1-1/2)
=21+63/64