cos(2/π+2x)
=cos[2(Pi/4+x)]
=[cos(Pi/4+x)]^2-[sin(Pi/4+x)]^2
=1-[sin(Pi/4+x)]^2-[sin(Pi/4+x)]^2
所以:2sin^2(π/4+x)=1-cos(π/2+2x)
这一步是公式:cos2x=(cosx)^2-(sinx)^2
cos(2/π+2x)
=cos[2(Pi/4+x)]
=[cos(Pi/4+x)]^2-[sin(Pi/4+x)]^2
=1-[sin(Pi/4+x)]^2-[sin(Pi/4+x)]^2
所以:2sin^2(π/4+x)=1-cos(π/2+2x)
这一步是公式:cos2x=(cosx)^2-(sinx)^2