1/x(X+2)+1/(X+2)(x+4)+.1/(x+8)(x+10)=1/3x
1个回答
X=5
所有的式子都化成 1/(X+2)(x+4)={1/(X+2)-1/(X+4)}/2
原等式等于10/X(X+10)=2/3X
X的平方=5X
X不等于0,所以X=5
相关问题
4【2x-1】-【10x+1】=3【2x+1]-12 x+3\4-2-3x\8=5\2
(1)4x-1.2=10.8-4x (2)1.2x+8.5=5x-1 (3)1.8-2.4x=8x-0.72速喥
(1/1-x)-(1/1+x)-(2x/1+x^2)-(4x^3/1+x^4)-(8x^7/1+x^8)
1/1*2x+1/2*3x+1/3*4x+1/4*5x+1/6*7x+1/7*8x+1/8*9x+1/9*10x=1/1
x1+5x2-x3-x4=-1x1-2x2+x3+3x4=33x1+8x2-x3+x4=1
求方程组X1-3X2-2X3-X4=1 3X1-8X2-4X3-X4=0 -2X1+X2-4X3+2X4=1 -X1-2
求线性方程组x1-3x2-2x3-x4=1,3x1-8x2-4x3-x4,-2x1+x2-4x3+2x4=1,-x1-2
(1-1/2)x(2-2/3)x(3-3/4)x……x(8-8/9)x(9-9/10)
x+1/10-x-1/5=1 x/12-2x-1/20=3x+4/8-
1/x(x+2)+1/(x+2)(x+4)+...+1/(x+8)(x+10)=5/24x