Question

(-2x-1)^2乘以(2x-1)^2-16(x+3)^2乘以（x-3）^2

Answer 1

(-2x-1)^2乘以(2x-1)^2-16(x+3)^2乘以(x-3)^2

=(2x+1)^2乘以(2x-1)^2-16(x+3)^2乘以(x-3)^2

=[(2x+1)(2x-1)]^2-16[(x+3)(x-3)]^2

=(4x^2-1)^2-16(x^2-9)^2

=(4x^2-1)^2-[4(x^2-9)]^2

={(4x^2-1)+[4(x^2-9)]}{(4x^2-1)-[4(x^2-9)]}

=(8x^2-37)*35

=280x^2-1295