第3题有问题.
[s(1)]^(1/2) + [s(2)]^(1/2) = a(1) = 1 = 1 + [s(2)]^(1/2),
s(2)=0=a(1)+a(2)=1+a(2),a(2)=-1.
-1 = a(2)=[s(2)]^(1/2) + [s(3)]^(1/2) = [s(3)]^(1/2)>0,矛盾.
第3题有问题.
[s(1)]^(1/2) + [s(2)]^(1/2) = a(1) = 1 = 1 + [s(2)]^(1/2),
s(2)=0=a(1)+a(2)=1+a(2),a(2)=-1.
-1 = a(2)=[s(2)]^(1/2) + [s(3)]^(1/2) = [s(3)]^(1/2)>0,矛盾.