解
1/x+1/y=5
即(y+x)/xy=5
∴y+x=5xy
∴(2x+3xy+2y)/(x-2xy+y)
=[2(x+y)+3xy]/[(x+y)-2xy]
=[2×5xy+3xy]/(5xy-2xy)
=(13xy)/(3xy)
=13/3
x+4>0
x>-4
2x+5
解
1/x+1/y=5
即(y+x)/xy=5
∴y+x=5xy
∴(2x+3xy+2y)/(x-2xy+y)
=[2(x+y)+3xy]/[(x+y)-2xy]
=[2×5xy+3xy]/(5xy-2xy)
=(13xy)/(3xy)
=13/3
x+4>0
x>-4
2x+5