Question

设函数f(x)=ax5+bx3+cx+1且f(π)=-1,求f（-π）的值,坐等.

Answer 1

f(x)=ax5+bx3+cx+1

f(-x)=a(-x)5+b(-x)3+c(-x)+1

=-ax5-bx3-cx+1

=-(f(x)-1)+1

=-f(x)+2

f(π)=-1

故f(-π)=-f(π)+2=3