(1)n(CuCl2):n(CaCl2)=1:2,
w(CuCl2)=m(CuCl2)/[m(CuCl2)+m(CaCl2)]=n1M1/(n1M1+n2M2)=n1M1/(n1M1+2n1M2)=M1/(M1+2M2)=136/(136+2*111)=38%
(2)设氯化铜xmol,则氯化钙2xmol,由2x+4x=2,得x=1/3,m=m1+m2=1/3*136+2/3*111=119.3g
(1)n(CuCl2):n(CaCl2)=1:2,
w(CuCl2)=m(CuCl2)/[m(CuCl2)+m(CaCl2)]=n1M1/(n1M1+n2M2)=n1M1/(n1M1+2n1M2)=M1/(M1+2M2)=136/(136+2*111)=38%
(2)设氯化铜xmol,则氯化钙2xmol,由2x+4x=2,得x=1/3,m=m1+m2=1/3*136+2/3*111=119.3g