Question

(2+2i)^4/(1-根号3i)^5复数的计算

Answer 1

针对你的题目,将复数写成指数形式算是较为简便的：

exp(iπ/4)=cos(π/4)+isin(π/4)=(1+i)/√2

exp(-iπ/6)=(1-i√3)/2

所以原式=[(2√2)^4]exp(iπ)/{(2^5)(exp(-i5π/6)}

=-2/exp(-i5π/6)

=-2exp(5iπ/6)

=-1+√3