2n(2n+2)(2n+4)(2n+6)+16因式 - 知识问答

2n(2n+2)(2n+4)(2n+6)+16因式分解

1个回答

2n(2n+2)(2n+4)(2n+6)+16
=16n(n+1)(n+2)(n+3)+16
=16[n(n+3)(n+1)(n+2)+1]
=16[(n²+3n)(n²+3n+2)+1]
=16[(n²+3n)²+2(n²+3n)+1]
=16[(n²+3n+1)²

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