consider: sin(A-B)= sinAcosB-cosAsinB
2[(√3/2)sin(wx+φ)-(1/2)cos(wx+φ)]
=2[sin(wx+φ)cos(π/6)-cos(wx+φ)sin(π/6)]
=2sin(wx+φ-π/6)
2[√3/2sin(wx+φ)-1/2cos(wx+φ)] =2sin(wx+φ-π/6)
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