Question

将1.721gcaso4.xH2o加热,使其失去全部结晶水,这是剩余固体物质的质量是1.361g,计算1mol此结晶水合

Answer 1

CaSO4的质量为1.361g,结晶水的质量==1.721-1.361==0.36g,

n(CaSO4)=1.361/136=0.01 mol;n(H2O)=0.36/18=0.02 mol,

CaSO4.xH2O==CaSO4 + x H2O

1 x

0.01 0.02

所以x=2 mol