Question

已知a-c=-6,则(a-b)2+2(a-b)(b-c)+(c-b)2的值是

Answer 1

(a-b)^2+2(a-b)(b-c)+(c-b)^2

= (a-b)(a-b+b-c) + (b-c)(a-b+b-c)

= -6(a-b)-6(b-c)

=-6(a-c)

=36