1、两个式子相减:
x2-xy-(xy-y2)=5-(-3)
x2-xy-xy+y2=8
所以:3( x2-xy-xy+y2)=8×3=24
2、(3x-4y+5xy)-(2x-3y)+5xy
=3x-4y+5xy-2x+3y+5xy
=x-y+10xy
=3+10×5
=3+50
=53
1、两个式子相减:
x2-xy-(xy-y2)=5-(-3)
x2-xy-xy+y2=8
所以:3( x2-xy-xy+y2)=8×3=24
2、(3x-4y+5xy)-(2x-3y)+5xy
=3x-4y+5xy-2x+3y+5xy
=x-y+10xy
=3+10×5
=3+50
=53