1.分解因式3x2-12-8a+20x22.化简1/(x2+x)+1/(x2+3x+2)+1/(x2+5x+6)+1/(

2个回答

  • 1、原式=2(3-6-4a+20)

    =2(17-4a)

    2、原式=1/x(x+1) + 1/(x+1)(x+2) + 1/(x+2)(x+3) + 1/(x+3)(x+4)

    =[(x+2)+x]/x(x+1)(x+2) + [(x+4)+(x+2)]/(x+2)(x+3)(x+4)

    =(2x+2)/x(x+1)(x+2) + (2x+6)/(x+2)(x+3)(x+4)

    =2/x(x+2) + 2/(x+2)(x+4)

    =[2(x+4)+2x]/x(x+2)(x+4)

    =8/x(x+2)(x+4)

    第3题的题目,第二部分两个括号中间应该有个"/",最后一个括号里的应该是不是(a^2-4)?

    那么这题应该如下解.

    原式=(a2+3a+3)/(a+1)(a+2) + (a2+3a-2)/(a+2)(a-2) +

    (1+2a-2a2)/(a+2)(a-2)

    =(a2+3a+3)/(a+1)(a+2)

    + [(a2+3a-2)+(1+2a-2a2)]/(a+2)(a-2)

    =(a2+3a+3)/(a+1)(a+2) + (-a2+5a-1)/(a+2)(a-2)

    =(a2+3a+3)(a-2)/(a+1)(a+2)(a-2)

    + (-a2+5a-1)(a+1)/(a+2)(a-2)(a+1)

    =[(a3-2a2+3a2-6a+3a-6)+(-a3-a2+5a2+5a-a-1)]/(a+2)(a-2)(a+1)

    =(5a2+a-7)/(a+2)(a-2)(a+1)