Question

sin^2（θ）+4cosθ/sin(90-θ) -1/tan(90-θ)

Answer 1

[sin^2(θ)+4cosθ]/sin(90-θ)-1/tan(90-θ)

=[sin^2(θ)+4cosθ]/cos(θ)-1/cotθ

=[sin^2(θ)+4cosθ]/cos(θ)-sin(θ)/cosθ

=[sin^2(θ)-sinθ+4cosθ]/cosθ

={sin(θ)[sin(θ)-1]+4cosθ]/cosθ

=tanθ(sinθ-1)+4