1.(x+1)(x-1)-(x+2)(x-3)=9 x多少 2.(3x+4)(3x-4)<
3个回答
1.x^2-1-(x^2-3x+2x-6)=9
=>x^2-1-x^2+3x-2x+6=9
=>x+5=9
=>x=4
2.展开得
9x^2-16 -16 9x>38
=> x>38/9
相关问题
2(x-2)+2=x+1 2(x-2)-3(4x-)=9(1-x) 7(2x-1)-3(4x-1)=4(3x+2)-1
计算(1)(3x+4)(3x-4) (2)(2x+1)(2x+3) (3)(9x+4y)(9x-4y)
(x+4)(x^2+16)(x-4),(x-1/3)(x^2+1/9)(x+1/3),
x1+x3+x4=7 x2+x3+x4=6 x2+x1+x4=8 x2+x1+x3=9 求x1 x2 x3 x4 是多少
(3x^2+9x+7)/(x+1)-(2x^2+4x-3)/(x-1)-(x^3+x+1)/(x^2-1)=
(3x^2+9x+7)/(x+1)-(2x^2+4x-3)/(x-1)-(x^3+x+1)/(x^2-1)=
9x+6x²-3(x-2/3x²)其中x=-1 (2)1/2(2x-6x-4)-4(-1+x+1/4
X-(1/4+3)-1/3{(X-1/4X+3)}-2-1/2{X-(X-1/4X+3)-1/3(X+1/4X+3)-2
1、下列变形:3(x-1)=3x-1,-(x-2)=-x+2,-(4x-1)=-4x-1,3(x-3)=3x-9,正确的
1、下列变形:3(x-1)=3x-1,-(x-2)=-x+2,-(4x-1)=-4x-1,3(x-3)=3x-9,正确的