等比数列{an};设公比为q;
S9=a1*(1-q^9)/(1-q);
S3=a1(1-q^3)/(1-q);
S6=a1(1-q^6)/(1-q)
若S9是S3和S6的等差中项:
所以q0)Sn单调递增;S9>S3>S6;2S9>S3+S6
2S9=S3+S6;
因为q0舍去)q^3=-1/2;
a7=a1*q^6=2*(q^3)^2=2*(-1/2)^2=1/2
等比数列{an};设公比为q;
S9=a1*(1-q^9)/(1-q);
S3=a1(1-q^3)/(1-q);
S6=a1(1-q^6)/(1-q)
若S9是S3和S6的等差中项:
所以q0)Sn单调递增;S9>S3>S6;2S9>S3+S6
2S9=S3+S6;
因为q0舍去)q^3=-1/2;
a7=a1*q^6=2*(q^3)^2=2*(-1/2)^2=1/2