GMAT数学条件题,麻烦解释清楚点并列出算式.

3个回答

  • Volume:

    Let S the area need to paint,so in every liter:

    A paint area of S/40

    B paint area of (S/40)*(3/4)=3S/160:

    The requirement volume of B is 160/3 L.

    Time:

    A cost 100H.

    B cost (1+1/3)100 = 400/3 H

    Using Paint A:

    The cost of 40L A is 240.00

    The cost of labor of 100H is 3600.00

    Total cost 3840.00

    Using Paint B:

    The cost of 160/3 L B is 240.00

    The cost of labor of 400/3H is 4800.00

    Total cost 5040.00

    Paint A is cheape