Question

Y=xloga(x^2+x-1) Y=log2((x-1)/(x+1)) 求导数,

Answer 1

1:

y'=x*[loga(x^2+x-1)]'+loga(x^2+x-1)

=x*(2x+1)/[lna*(-1 + x + x^2)]+loga(x^2+x-1)

=(2x^2+x)/[lna*(-1 + x + x^2)]+loga(x^2+x-1)

2:

y'=(x+1)/[Ln2(x-1)]*[(x - 1)/(x + 1)]'

=(x+1)/[Ln2(x-1)]*[(x+1)-(x-1)]/[(x+1)^2]

=2/[( x^2-1) Ln2]