已知(x-y-2)²+|x+y+1|=0,求(x-y)²+3(x+y)³-2(x-y)&s
1个回答
(x-y-2)²+|x+y+1|=0
因为平方和绝对值都大于等于0,和为0,所以两部分均为0
x-y-2=0
x+y+1=0
得到
x-y=2
x+y=-1
代入后面式子
原式=4-3-8+1=-6
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