Question

计算(3+1)(3^2+1)……(3^（2^12）+1)

Answer 1

(3+1)(3^2+1)……[3^(2^12)+1]

=(3-1)(3+1)(3^2+1)……[3^(2^12)+1]/2

=(3^2-1)(3^2+1)……[3^(2^12)+1]/2

=[3^(2^2)-1]……[3^(2^12)+1]/2

=[3^(2^24)+1]/2