(1)(x+1) 5,
=(x+1) 2×(x+1) 2×(x+1),
=(x 2+2x+1)(x 2+2x+1)(x+1),
=(x 4+4x 3+6x 2+4x+1)(x+1),
=x 5+5x 4+10x 3+10x 2+5x+1,
∵(x+1) 5,
=ax 5+bx 4+cx 3+dx 2+ex+f,
∴a=1,b=5,c=10,d=10,e=5,f=1,
∴(1)a+b+c+d+e+f=1+5+10+10+5+1=32.
(2)b+c+d+e=5+10+10+5=30.
(3)a+c+e=1+10+5=16.