Question

已知sinα-√3cosα=(2m-3)/(2-m),求m的取值范围

Answer 1

sinα-√3cosα=(2m-3)/(2-m)

2*(1/2*sinα-√3/2*cosα)=(2m-3)/(2-m)

2*(sinαcosπ/3-cosαsinπ/3)=(2m-3)/(2-m)

2*sin(α-π/3)=(2m-3)/(2-m)

sin(α-π/3)=(2m-3)/(4-2m)

-1<=sin(α-π/3)<=1

(2m-3)/...