答案是1/4
∫cos³x*sinx dx,from 0 to π/2
=∫cos³x*d(-cosx)
=(-1/4)cos^4x
=(-1/4)[cos(π/2)]^4 - (-1/4)[cos(0)]^4
=(-1/4)(0) + (1/4)(1)^4
=1/4
∫【π/2 0】(cos^3)xsinxdx
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