(sin3xsinx)sin2x+(cos3xcosx)cos2x =1/ 2 [(cos2x-cos4x)sin2x+
1个回答
积化和差公式
sinasinb=1/2[cos(a-b)-cos(a+b)]
cosacosb=1/2[cos(a-b)+cos(a+b)]
相关问题
求证:cos3xcosx+sin^22x=sin3xsinx+cos^22x.
(sin2x)^2+sin2xcosx-cos2x=1
化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x
有关高一三角函数变换,求证:2(sin²x)²+¾ sin²2x+5(cos²x)²- cos3xcosx=2+2cos
求cos(4sinx)、cos(3sinx)、sin(cosx)、sin(cos2x)、sin(cos3x)、sin(2
cos1/2x-cos3/2x怎嫫等于2sin2xsinx
1、求证:2sin四次方x+¾sin²2x+5cos四次方x-cos3xcosx=2+2cos&
1.y=cos^4x+sin^4x 求周期 2.y=(sin2x+sin(2x+π/3))/( cos2x+cos(2x
求函数y=[sin2x+sin(2x+π/3)-cos1/2﹙π-4x﹚]/[cos2x+cos﹙2x+π/3﹚-sin
求证(cos^2x-sin^2x)(cos^4x+sin^4x)+1/4sin2xsin4x=cos2x