sinA=120 sinB+sinC最小值怎么算
2个回答
sinB+sinC=sin(60-c)+sin(c)=sin(c+60)
因为c大于0小于60.所以c+60大于60小于120
故sinB+sinC大于二分之根号3,小于1.当c=30时取最大值1
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