14.5-(2t+6)/5=1.5t-0.24t+1.68
14.5-0.4t-1.2=1.26t+1.68
1.66t=11.62
t=7
14.5-[2(t+3)]/5=0.15t/0.1-(0.4t-2.8)/0.6
1个回答
相关问题
-
0.5*g*(T+0.15)^2-0.5*g*T^2=2
-
解方程：（1）2t-4=3t+5；（2）[1.5x−1/3−x0.6＝0.5
-
①x2-8x-7=0②x2+14x-15=0③t2-(2/3)t-(8/9)=0④4(x+3)2-9(x-2)2=0
-
14.5-5／2﹙x+3﹚＝0.1／0.15x－0.6／0.4x－2.8
-
matlab能手进~t=[0.25 0.5 0.75 1 1.5 2 2.5 3 3.5 4 4.5 5 6 7 8 9
-
试求向量组 =(1,1,2,2)T, =(0,2,1,5)T, =(2,0,3,-1)T, =(1,1,0,4)T的秩和
-
几道初一方程题（一）（1-2X）/6+（X+1)/3=1-（2X+1）/4（二）(4t-1.5)/0.5-(5t-0.8
-
解方程．（1）4{32[23(x4−1)−2]−x}＝5；（2）[0.4t+0.1/0.5−0.01−0.2t0.04＝
-
2t+（t-1）/0.2=（3-2t）/0.4+2
-
当t取何值时,向量组(1,2,-1,1)^T,(2,0,t,0)^T,(0,-4,5,-2)^T线性相关?