Question

A,O,B在同一条直线上,OC平分角AOD,OE平分角BOD.写出图中角COD的余角和补角.

Answer 1

∵OC平分∠AOD,OE平分∠BOD

∴∠AOC=∠COD,∠DOE=∠EOB

又：∠AOC+∠COD+∠DOE+∠EOB=∠AOB=180°

∴∠COD+∠DOE=1/2∠AOB=90°

∴∠DOE=90°-∠COD,即∠COD的余角是∠DOE

∵∠AOC+∠COB=∠AOB=180°

∴∠AOC=180°-∠COB

又：∠AOC=∠COD

∴∠COD=180°-∠COB,即∠COB是∠COD的补交