sina-cosa=根号2,求sin2a,cos2a.
2个回答
(sina-cosa)²=(根号2)²
sin²a+cos²a-2sinacosa=2
1-sin2a=2
∴sin2a=-1
sin²2a+cos²2a=1
∴cos²2a=0
cos2a=0
相关问题
已知sina+cosa=p,求(1)sina*cosa(2)sin^2a-cos^2a(3)sin^3a+-cos^3a
Sina+Cosa=1/5 求Sin2a,Cos2a
sin(π/2+a)=cosa,cos(π/2+a)=-sina,sin(π/2-a)=cosa,cos(π/2-a)=
若cos2a/sin(a-TT/4)=负根号2/2,则cosa+sina=?
1.若COS2a/sin(a-兀/4)=-(根号2)/2.则COSa+sina=?
已知sina-cosa=1/2,求sin2a+cos2a
2sin^a-cos^a+sina*cosa-6sina+3cosa=0
cos2a/sin(a-π/4) =-根号(2)/2,则cosa+sina的值为?
(2 cosa-sina)(sina+cosa+3)=0,那(2cos²a+sin2a)/(1+tana)=?
sina+sinβ=根号2/2,求cosa+cosβ的范围