已知两个等差数列{an}和{bn}的前n项和分别为An和Bn,且An/Bn=(7n+41)/(n+3)
1个回答
答案是C
把n+3做为整体化简:
An/Bn=[7(n+3)+20]/(n+3)=7+20/(n+3)
很显然,只要20/(n+3)是整数就可以了,n=1,n=2,n=7 n=17
答案就是C 4个
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