Question

根号2x²+2x-根号2=0 和（x+1）（2x-3）=1

Answer 1

两边除以√2

x²+√2x=1

x²+√2x+1/2=1+1/2

(x+√2/2)²=3/2

x+√2/2=±√6/2

x=(-√2-√6)/2,x=(-√2+√6)/2

(x+1)(2x-3)=1

2x²-x-3=1

x²-x/2=2

x²-x/2+1/16=2+1/16

x-1/4=±√33/4

x=(1-√33)/4,x=(1+√33)/4