Question

2x²+3x-2=0 6x²+7x-3=0 3x²-14+16=0 （3x+2）²

Answer 1

2x²+3x-2=0

(2x-1)(x+2)=0

x=1/2或x=-2

6x²+7x-3=0

(3x-1)(2x+3)=0

x=1/3或x=-3/2

3x²-14x+16=0

(3x-8)(x-2)=0

x=8/3 x=2

（3x+2）²-4（x-3)²=0

[(3x+2)+2(x-3)][(3x+2)-2(x-3)]=0

(5x-4)(x+8)=0

x=4/5 x=-8