Question

若七十三克质量分数为百分之二十的盐酸与一百二十七克氢氧化钠溶液恰好完全中和,试计算反应后所的溶液中溶

Answer 1

HCl的质量 = 73 * 0.2 = 14.6 g

设产生NaCl的质量是x

HCl + NaOH = NaCl + H2O

36.5 58.5

14.6 g x

36.5/58.5 = 14.6 g / x

x = 23.4 g

溶质NaCl质量分数 = 23.4 / (73+127) * 100% =11.7%

即反应后所的溶液中溶质质量分数为11.7%