答案为1+根号2
Xn=2+1/Xn-1
两边取极限,由极限的性质知limXn=2+1/limXn-1
又limXn=limXn-1,设A=limXn=limXn-1,则A=2+1/A,解得A=1+根号2(舍去负值)