Question

讨论分段函数f(x)=1/1+e^1/x 当x不等于0 ；f(x)=0当x等于0在x=0处的左右连续

Answer 1

lim f(x) =lim 1/[1+e^(1/x)]=1/1=1;

//x→0-,则1/x→-∞;则e^(1/x)→0.

lim f(x) =lim 1/[1+e^(1/x)]=1/(+∞)=0;

//x→0+,则1/x→+∞;则e^(1/x)→+∞

∴

只有右连续;