Question

标况下将0.008molCH4和O2混合气体点燃,完全燃烧后,将生成的气体通入100ml.0.02mol/l石灰水中得到

Answer 1

Ca(OH)2 + CO2 = CaCO3 + H2On(Ca2+) = 0.02*100/1000 =0.002 moln(CaCO3) = 0.1/100 =0.001 mol < n(Ca2+)说明生成的CO2完全转化为CaCO3.而且n(CO2) = n(CaCO3) =0.001 mol.CH4 + 2O2 = CO2 + 2H2O参加反应的气体的...