(san+tbn)-(san-1+tbn-1)
=(san-san-1)+(tbn-tbn-1)
=s(an-an-1)+t(bn-bn-1)
因为an-an-1为常数,bn-bn-1也为常数
所以s(an-an-1)+t(bn-bn-1)也为常数
所以{san+tbn}也是等差数列
(san+tbn)-(san-1+tbn-1)
=(san-san-1)+(tbn-tbn-1)
=s(an-an-1)+t(bn-bn-1)
因为an-an-1为常数,bn-bn-1也为常数
所以s(an-an-1)+t(bn-bn-1)也为常数
所以{san+tbn}也是等差数列