计算2/3(1+1/3)(1+1/9)(1+1/81)(1+1/81²)
1个回答
=8/9*10/9*82/81*81*(81*81+1)/81*81
=(81*81-1)/81*81
相关问题
计算:1+1/3+1/9+1/27+1/81+1/243+1/729
按规律填数.(1)1,3,9,27,81,______(2)1,4,9,16,______,49,64(3)90,81,
1/3+1/9+1/27+1/81+1/243+1/729
1-1/3-1/9-1/27-1/81-1/243-1/729=?
的规则填空 (1)1 3 3 9 ( ) 81 ( ).
计算:1/(根号0.25)+(1/27)^-1/3+根号[(lg3)^2-lg9+1]-lg1/3+81^0.5log3
9.81*0.1+0.5*9.81+0.04*98.1简便计算
1-1/3-1/9-1/27-1/81-1/243-1/729-1/2187
81^1/2-(1/8)^-1+3^0=?
找规律填数.1,3,9,______,81,______,______;1,3,7,15,______,63;1,1,2