limn→∞ n(√n²+1 -n)
2个回答
limn→∞ n[√(n²+1)-n][√(n²+1)+n]/[√(n²+1)+n]
=limn→∞ n/[√(n²+1)+n]
=limn→∞ 1/[√(1 +1/n²)+1]
=1
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