Question

在C5H10O2的同分异构体中,只含有一个酯基的有机物共有多少种?

Answer 1

9种

HCOOCH2CH2CH2CH3

HCOOCH2CH(CH3)2

HCOOCH(CH3)CH2CH3

HCOOC(CH3)3

CH3COOCH2CH2CH3

CH3COOCH(CH3)2

CH3CH2COOCH2CH3

CH3CH2CH2COOCH3

(CH3)2CHCOOCH3

能水解的该是酯把,质量相等说明生成

M酸=M醇=[M(C5H10O2)+M(H20)]/2=120/2=60g/mol(M指摩尔质量)

结合醇的通式CnH2n+2O和酸的通式可知为C3H80和C2H402

满足以上的酯有2种

CH3COOCH2CH2CH3

CH3COOCH(CH3)2