Question

已知函数f(x)=根号3sinx-cosx,x∈〔-π/2,π/2〕

Answer 1

1、

由x范围则cosx>0

sin²x+cos²x=1

所以cosx=3/5

所以f(x)=(4√3-3)/5

2、

f(x)=2(sinx*√3/2-cosx*1/2)

=2(sinxcosπ/6-cosxsinπ/6)

=2sin(x-π/6)

-π/2