设a>b>0,a²+b²-6ab=0,则b-a分之a+b的值等于?
1个回答
a²+b²-6ab=0
(a-b)²=4ab a>b>0 ∴ a-b= 2√(ab)
(a+b)²=8ab a+b=2√(2ab)
(a+b)/(b-a)= - √2
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