只需要把式子乘一个(2^2-1)除一个(2^2-1)就可以了
(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
＝(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)/(2^2-1)
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)/(2^2-1)
=.
=(2^64-1)/(2^2-1)
=(2^64-1)/3
(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
2个回答
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