Question

向20克稀硫酸中滴入浓度为10%的氯化钡溶液,至不再产生沉淀为止,用去氯化钡溶液208g,求此稀硫酸的质量分数

Answer 1

1n(H2SO4)=n(BaCl2)= 208*10%/(137+35.5)=0.121 molw(H2SO4)=n(H2SO4)*98/20=0.121*98/20= 59%2 n(Cu(OH)2)=n(CuSO4)=200*16%/160=0.2 moln(Na2SO4)=n(CuSO4)=0.2 molw(Na2SO4)=0.2*(46+96)/(200+200-0.2*98)=7.5%20...